8th grade math help

[onyx jay]

I tried doing ii) but its not correct can someone help

[pseudo rivet]

@onyx jay no wait i know that book is it Singaporean

i think I have the book

[onyx jay]

idk if is

its school book

[pseudo rivet]

ah

k mb

[onyx jay]

shinglee

[pseudo rivet]

yes thats the one I have

singaporean then

[onyx jay]

yes it's Singaporean then

[pseudo rivet]

this?

Anyway abt the question

To find HC

We must subtract BH from HC.

Try to find expressions of BH and HC in terms of the known length AB and the known angle ABC

@onyx jay

[onyx jay]

yes!

[onyx jay]

whats tve ABC angle

[pseudo rivet]

damn i do too much

[onyx jay]

the*

[pseudo rivet]

56 right

[onyx jay]

oh yes

[pseudo rivet]

Its known

Yes

[onyx jay]

I know bh

Its 4.98

[pseudo rivet]

you know you have no life when you can find the exact assessment book 😭

[pseudo rivet]

ah okay

Now can you find BC?

[onyx jay]

No because idk bh

wait

let me try

[marble nebula]

19.19…..

[pseudo rivet]

aiyo

[onyx jay]

?

[marble nebula]

whats the answer?

[pseudo rivet]

Let @onyx jay try

[onyx jay]

10.9

[marble nebula]

Alr mb😭🙏

[onyx jay]

in the book

[marble nebula]

Nice

[marble nebula]

Hmm

[onyx jay]

but im trying to find it

[marble nebula]

Idk

[pseudo rivet]

???

[onyx jay]

by myself

[pseudo rivet]

pro attitude

[onyx jay]

yes

because my finals are coming in 15

[pseudo rivet]

okay so you found BH right

[onyx jay]

yea

[pseudo rivet]

good luck fr

Which country

[onyx jay]

bangladesh

[pseudo rivet]

(if you dont mind)

Ah

[onyx jay]

its ok

[pseudo rivet]

.

[onyx jay]

hold on in trying

[marble nebula]

mb

[pseudo rivet]

!nosols

[rigid plank]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[marble nebula]

Alr

[pseudo rivet]

ty sry

[marble nebula]

😭🙏

can i give a hint 😘

[pseudo rivet]

up to you

[onyx jay]

wait

[pseudo rivet]

Id let OP try first

[onyx jay]

Do I find ac

AC*

[pseudo rivet]

Theres no need to

which trig function of ABC

[marble nebula]

if u want

[onyx jay]

56?

[pseudo rivet]

Relates the known AB to the unknown BC?

[pseudo rivet]

wat

[onyx jay]

what

[pseudo rivet]

Which trig function of the angle ABC relates AB to BC

sin tan or cos

[onyx jay]

ohh

what

[pseudo rivet]

mb if i was not clear

[onyx jay]

which one

[pseudo rivet]

Its cosine btw

Adj/hyp

Wait

[hard coral]

another idea if u solved A is that u could look for 2 proportional triangles

[onyx jay]

cos?

[pseudo rivet]

ah yes similarity didnt see that mbmb

[pseudo rivet]

yes

[onyx jay]

whats that

[pseudo rivet]

Can you write out the formula for cos (ABC)?

[onyx jay]

okay

[hard coral]

2 triangles that have the same angles

[pseudo rivet]

Like which lengths is it in diagram ty

[pseudo rivet]

whats it in this case

[onyx jay]

wait im confused what you're asking

[pseudo rivet]

Whats the A and H in the diagram

[onyx jay]

isnt AH=7.38

[pseudo rivet]

nono

k wait

[onyx jay]

okok

[pseudo rivet]

||cos ABC = adjacent / hypothenuse = AB/BC||

[hard coral]

if 2 triangles have equal angles let s say ABC and DEF then AB/DE=BC/EF=AC/DF

[pseudo rivet]

do you get it now

@onyx jay

[onyx jay]

no

[onyx jay]

we didn't do that yet I think

[onyx jay]

to find bc

I need to find

hc

how do I do that

[pseudo rivet]

wait youre getting it mixed up

We need to find HC

so we need to find BC and BH and then subtract

You calculated BH already

[onyx jay]

Yes

Then I need to find hc

oh yes

[pseudo rivet]

we only need to find BC

And were done

[onyx jay]

find bc

[pseudo rivet]

Because cos 56 = AB/BC is known

And AB is known

We can find BC

you follow @onyx jay

[onyx jay]

okay

I tried

I did tan

[pseudo rivet]

why

its cos

[onyx jay]

what

[pseudo rivet]

,w cos 56

[drowsy ermine]

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[pseudo rivet]

AB/BC is 9.8/BC is approximately 0.56

then we know BC

Right

[onyx jay]

Can u write it out

[pseudo rivet]

$\cos(56) = \frac{AB}{BC} = \frac{9.8}{BC} = 0.56$

Whats BC

[drowsy ermine]

Carbonite

[onyx jay]

bc is 0.56

isnt*

[pseudo rivet]

wdym

Ah

But cos (56) is 0.56

So 9.8/BC is 0.56

[onyx jay]

shat

what

[pseudo rivet]

cos (ABC) is AB/BC right

[marble nebula]

yes it is ig?

Just sum all angles

to find angle acb

or angle ach

[onyx jay]

what

cos abc

56

[marble nebula]

Then use value of AC and use tan

[onyx jay]

AB/Ac

SDO I FIND AC

[marble nebula]

Yea

Ig?

[onyx jay]

wait how'd u get 34

[pseudo rivet]

ty

[pseudo rivet]

90-56

[onyx jay]

why do you minus them?

[sturdy schooner]

Total internal angle of triangle is 180 degree, 2 angles are given ie, 90 and 56, so remaining is 34

[marble nebula]

fr

[marble nebula]

sum of all angles of a traingle =180

180= 90+56+x

[onyx jay]

OH MY GOD

IM SO STUPID

I LUTERALLY KNEW THE ANSWER

I WROTE IT

[onyx jay]

THERES NO NEED FOR THAT

[marble nebula]

lmao

[pseudo rivet]

sry if I couldnt help that much @onyx jay

[marble nebula]

me too lol

sry

[onyx jay]

its ok dw