Algebra?

[olive night]

'Cause I don't study math in eng, I can't explain the way to solve it for u

[radiant stirrup]

you don't need to find x. Just multiply both equations. You'd get 2^(x+y) on the LHS and Something like 2^(n

2^(n+1) on RHS

Substitute x+y=8, which is given in the question

bases are same therefore powers will also be equal

I think I made a mistake calculating the power on the RHS

But the method is same

[olive night]

Could you explain the meaning of the term "RHS" for me, please?

[radiant stirrup]

Right hand side- the part of an equation on the right side of the equal sign

[olive night]

Oh, i got it. thanks

[radiant stirrup]

my pleasure🥰

[minor pasture]

Multiply both sides by$2^{y}$

[restive rivet]

Enterlessguy

[minor pasture]

We get $2^{x+y}=2^{\frac{13}{6}}2^{n}$

[restive rivet]

Enterlessguy

[minor pasture]

$\iff 8=2^{n+\frac{13}{6}}$

$\iff 3=n+\frac{13}{6}$.

[restive rivet]

Enterlessguy

Enterlessguy

Enterlessguy

[minor pasture]

(I misread the question this is 2^{8} = rhs so after you take log we have 8=n+13/6

[feral oar]

.close