hence proved?? is this legit? is this the way to prove applied log rule??

[heavy fractal]

Yeah

[dense pewter]

how did you jump to the conclusion?

did you jump from the above to the conclusion?

[delicate copper]

this is correct

it could be quicker if you replace a with q^b, x with q^y

log(q^b,q^y) = (y/b)log(q,q) = y/b

there are many ways to prove it, using the other log rules

[marsh crypt]

i put the values in as i defined them.

[marsh crypt]

yes

[marsh crypt]

thanks

[marsh crypt]

ic, i have just started the basics and was concerned.