Solving e

[agile shale]

I d’ont understand your question

You want to know why the partial sum is expressed like that ?

[strong vine]

No.

Long story short.

He wants you to solve for n.

Or at least, gives an equation that contains all solution sets from that equation.

Which in my opinion, is worthless.

[wicked valley]

When i type a number for n, i want the result of the n sum of 1/x! To Equal (1+n^-1)^n
I Need it for something important and a suprise so i can't say it

[agile shale]

Aaaah

I see but have no idea have to do it sorry

Or i still don’t understand the question

[sullen fable]

it's just not true, though:
\vspace{6pt}

[\sum_{k=0}^2 \frac{1}{k!} = \frac{1}{0!} + \frac{1}{1!} + \frac{1}{2!} = 1+1 + \frac{1}{2} =2.5]

[(1+2^{-1})^2 = 1.5^2 = 2.25 \neq 2.5]

[fleet geyser]

HChan