#Help me
38 messages · Page 1 of 1 (latest)
What part do you not understand?
An equivalence relation is a relation $\sim:X\times X\to X$ which has $\forall x,y,z\in X$ \begin{enumerate}
\item $x\sim x$
\item $x\sim y\implies y\sim x$
\item $x\sim y$ and $y\sim z\implies x\sim z$
\end{enumerate}
Then you can say the set of elements which are equivalent to $x$ (denoted $[x]_{\sim}$) is called the equivalence class of $x$. Note that the choosing of $x$ as the representative was arbitrary.
SelahW
For example we can take $X=\mathbb{Z}$, and say $x\sim y$ if $x-y\mid 10$. Then there are 10 equivalence classes, e.g. [[3]={\dots,-17,-7,3,13,23,\dots}] or [[6]={\dots, -14,-4,6,16,26,\dots}]
SelahW
@vernal rock
what does Idea mean?
@cinder yoke
When you have a set and an equivalence relation defined on the set, you can mod out by the relation to get a new set. It's called the quotient set and it's elements are equivalence classes
This usually comes up in terms of some algebraic structure (group ring module etc) because normal subgroups, ideals, and submodules define a unique equivalence relation on their resp. structures
I just dont understand thing because i dont think like nlab
Yes it tries to be general, that's kind of the point
as i see they starting with quotient set not from its elements
and define classes as elements of set not vice versa
maybe i dont get things right
Well you start with the set X, and an equivalence relation $\sim$ on X. With that you get a new set $X/\sim$
SelahW
That's the quotient set
Everything that was simply equivalent in X is now equal in $X/\sim$
SelahW
like they say:
- X/~ exists
- [x]~ = [y]~ iff x ~ y
Yes
(also f: S -> S/~)
That's this
This is usually denoted with pi and I've always heard it called "the natural reduction map"
It sends each element to its equivalence class
With the example I gave above, we have our set $X=\mathbb{Z}$. The equivalence relation is $x\sim y\iff x-y\mid10$.
SelahW
Then we can form the quotient, and we get a new set $\mathbb{Z}/\sim$ where there are 10 elements, and elements are equal if they were equivalent in the other set.
SelahW
In the set $\mathbb{Z}$, 16 and 6 are equivalent because $16-6=10\mid10$. So the equivalence classes $[16]$ and $[6]$ are equal in the quotient.
SelahW
Again the cat lab definition is not the one I would choose if I were an undergrad or explaining it to an undergrad
Probably the way this should be learned is through group theory. Nobody generally just quotients a set lol, it is usually a quotient group, ring, or module
there set