#Help me

38 messages · Page 1 of 1 (latest)

uncut meadowBOT
cinder yoke
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What part do you not understand?

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An equivalence relation is a relation $\sim:X\times X\to X$ which has $\forall x,y,z\in X$ \begin{enumerate}
\item $x\sim x$
\item $x\sim y\implies y\sim x$
\item $x\sim y$ and $y\sim z\implies x\sim z$
\end{enumerate}
Then you can say the set of elements which are equivalent to $x$ (denoted $[x]_{\sim}$) is called the equivalence class of $x$. Note that the choosing of $x$ as the representative was arbitrary.

nocturne karmaBOT
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SelahW

cinder yoke
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For example we can take $X=\mathbb{Z}$, and say $x\sim y$ if $x-y\mid 10$. Then there are 10 equivalence classes, e.g. [[3]={\dots,-17,-7,3,13,23,\dots}] or [[6]={\dots, -14,-4,6,16,26,\dots}]

nocturne karmaBOT
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SelahW

cinder yoke
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@vernal rock

vernal rock
vernal rock
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@cinder yoke

cinder yoke
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When you have a set and an equivalence relation defined on the set, you can mod out by the relation to get a new set. It's called the quotient set and it's elements are equivalence classes

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This usually comes up in terms of some algebraic structure (group ring module etc) because normal subgroups, ideals, and submodules define a unique equivalence relation on their resp. structures

vernal rock
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I just dont understand thing because i dont think like nlab

cinder yoke
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Yes it tries to be general, that's kind of the point

vernal rock
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as i see they starting with quotient set not from its elements

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and define classes as elements of set not vice versa

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maybe i dont get things right

cinder yoke
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Well you start with the set X, and an equivalence relation $\sim$ on X. With that you get a new set $X/\sim$

nocturne karmaBOT
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SelahW

cinder yoke
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That's the quotient set

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Everything that was simply equivalent in X is now equal in $X/\sim$

nocturne karmaBOT
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SelahW

vernal rock
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like they say:

  • X/~ exists
  • [x]~ = [y]~ iff x ~ y
cinder yoke
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Yes

vernal rock
cinder yoke
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It sends each element to its equivalence class

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With the example I gave above, we have our set $X=\mathbb{Z}$. The equivalence relation is $x\sim y\iff x-y\mid10$.

nocturne karmaBOT
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SelahW

cinder yoke
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Then we can form the quotient, and we get a new set $\mathbb{Z}/\sim$ where there are 10 elements, and elements are equal if they were equivalent in the other set.

nocturne karmaBOT
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SelahW

cinder yoke
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In the set $\mathbb{Z}$, 16 and 6 are equivalent because $16-6=10\mid10$. So the equivalence classes $[16]$ and $[6]$ are equal in the quotient.

nocturne karmaBOT
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SelahW

cinder yoke
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Again the cat lab definition is not the one I would choose if I were an undergrad or explaining it to an undergrad

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Probably the way this should be learned is through group theory. Nobody generally just quotients a set lol, it is usually a quotient group, ring, or module

vernal rock
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there set

vernal rock
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Help me

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.solved