#Help :(
29 messages · Page 1 of 1 (latest)
$-3 < x < 1$or$x > 3$
munchkins
Alternative:
Don’t take any offence to this but wouldn’t it be better to show how to get the answer
igh
Solve inequalities $\frac {\frac {1}{x-3}}{\frac {x}{x}}>\frac {4}{x^{2}-9}$: ⇒ $-3 < x < 1$or$x > 3$
oh my faul
munchkins
Solve inequalities $\frac {\frac {1}{x-3}}{\frac {x}{x}}>\frac {4}{x^{2}-9}$: ⇒ $-3 < x < 1$or$x > 3$
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$-3 < x < 1$or$x > 3$
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hmm wait
Solve inequalities $\frac {\frac {1}{x-3}}{\frac {x}{x}}>\frac {4}{x^{2}-9}$: ⇒ $-3 < x < 1$or$x > 3$
munchkins
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<-∞,-4> U <-3, 0> U <0, 1> U <3, ∞> but how
First of all the question u asked is misleading
Is 1/x-3 the numerator and x the denominator
Or is 1 the numerator and x/x-3 the denominator
That is why the AI you used haves different answers
axkyn
Oh this is og problem 
0 is not in domain
see that in the ques, the denominator is a fraction, x-3 / x
so for domain of denominator, x should not be 0