please send help

[buoyant mist]

What's the problem?

[humble mauve]

I can’t figure out how to solve the rest

[buoyant mist]

What are you solving is what I meant

[humble mauve]

number 2,

sorry

“6” (2nd on the paper)

i can send the answer key if that helps

[buoyant mist]

Are you trying to find the shaded area?

[humble mauve]

yes

I’m just confused because all the other examples give the formula but these last three don’t

[buoyant mist]

$\int_2^32x+2dx$

[cerulean pivot]

SelahW

[humble mauve]

yes but i don’t know how to get there

because i know how to solve it but i don’t understand the getting there part

[buoyant mist]

Do you know what an integral is?

[humble mauve]

yes i do

but i had to go do first aid for the portion of the lesson we are talking about

[buoyant mist]

So we want the area under the curve from $x=2$ to $x=3$

[cerulean pivot]

SelahW

[buoyant mist]

(you can compare this to the first one, where we took the area from x=0 to x=3)

[humble mauve]

OHH

that makes sense now

the x axis of the shaded area

(two to three)

[buoyant mist]

Right 👍👍

[humble mauve]

then i just solve

okay just another question what about this one

[buoyant mist]

Hmm

So we don't want the area between the curve and the x axis, we want between the curve and the y axis

So integrate w.r.t y instead of x

[humble mauve]

i understand but don’t

[buoyant mist]

When we integrate, we have a function (of x) $f(x)=$whatever. Then we do $\int f(x)dx$ to measure area between that curve and the x axis. If we instead have a function of y, $f(y)=\dots$ then we can take the integral with respect to y, $\int f(y)dy$ to measure area between the curve and the y axis

[cerulean pivot]

SelahW

[humble mauve]

i think i got it

i got the area of the27

[buoyant mist]

So we can turn this into a function of y, by solving for x, $x=\pm\sqrt{y}$ (we only really need the positive part) then integrate that

[cerulean pivot]

SelahW

[humble mauve]

ohhh i get it now!

thank you so much!

[buoyant mist]

Np 🫡

[livid oar]

!done

[fallen kelp]

If you are done with this channel, please mark your problem as solved by typing .close

[livid oar]

.solved