#Help
167 messages · Page 1 of 1 (latest)
Jus draw all for graphs respective of their x cords
For0<=x<=2 , graph will be y=2x-x^2
Can u show me?
And same for all
I'll have to draw on paper
I'll try
@zenith marsh do u also need an explanation
If I don’t understand
What about the point 2,0
U just leave it as a closed circle?
Yea, since the next graph also starts on the point 2,0
Its open on 4,0 I didn't draw
What about pi
He’ll
Bloody hell
Closed circle at 4,pi and then continue till infinity
Correct, although I wouldn't recommend drawing the full parabola for the first part and draw the part only between 0 and 2
If its for a teacher
No
I can try
I messed up with continuity
And differentiability
Can u teach me now. I may understand in 3min
Sure, where exactly do u mess up in continuity
It means that if there is a function f(x) let's say, in an interval (a,b), f(x) gives all real values for a to b, on a graph you can think of this as 'y' giving a continuous line instead of breaking at one point and starting at another
Like it was in the first question at 0,4 the graph was not continuous on that point
Visually, just think of functions as graph, continuous graphs give us lines which do not break
They could be straight or curve
If a function is said to be continuous in the domain let's say [0,1), so its continuous from point 0 to barely point 1
When we get open brackets, that means its mostly a limit
I just know that they discontinuous when the limit didn’t exist
I seee
Yea, for a function, you sometimes find right limit and then left limit and then on the point, if they're equal then its continuous
If they're diff then it means the graph changed on either side of its neighborhood
Yeah
F’x and f’’x?
The first one is continuity?
No, ' on a function means we differentiated it
F'(x) is diff one time
F''(x) is diff to times
Did you take differentiation lessons as part of the calculus?
I haven’t done the test yet, if I passed I can take advanced maths in September
But my teacher gives me homework about this and I forgot what he said to me
They shouldve taught u that since they gave u a couple of questions
Maybe I was daydreaming in the class
Or they just talked about it for 10s
Well for starters and in theory, you should know that all points which are differentiable are also continuous,but all points which are continuous are not necessarily diff
Yeah I remember that
Diff a function is like finding its slope
This one?
I’m still confused
Yes
What part are u confused in
Okay see, take graph 4 on the pic u send me for an example ok? At 1,0 is it continuous or no?
How can we know if the derivative exists or not
No?
Where is graph 4
On graph 4, think of taking a limit on the graph, when limit goes to positive side of 1(on x axis) we get 2, when limit is on negative 1, we still get 2
Oh I see
If it contains an open circle then it’s not continuous
Yea
Now as u know derivative is slope of graph or simply on which angle the point is headed towards
On point(1,2) it is continuous but do u think it's diff?
Idk what is that means
Differentiability
Let me google it
Nope?
Similar to continuity , does the function have same derivative in the neighborhood of points, if yes then diff
Cuz that is a sharp turning point
Yea that's correct
Ok
Do u know why tho
No..
Only straight standing line/parallel to y axis have slope infinity
no..
0 slope is parallel to x axis
Okay, so when finding if a point diff or not, just like continuity,we check slopes on either side of the point like limits
It does,that's why its continuous
The point before 1,2 lies on which line
Are we talking about 4?
I don’t know the reason
The slope one is positive and one is negative
So it didn’t exist?
That's fine, left limit of point 1,2 lies on the slanting line before it, do u agree?
Yeah
Yess, the slopes are diff on the same point when we use limits, so the point has no actual slope hence its not diff
Get it?
Don't look at the extremes, limit means very very close to the point , so just anything except the actual point
Ok
Yup correct
If we take limits on 1,2 left limit is usually 0.99999 and right limit is usually 1.00001
Yeha ik that
Yeah
But quadratic also have 2 slopes
One is negative and one is positive
Didn’t convinced myself lol
That the diff does exist
Look at the point (1.00001,2)
When limit goes to 1.00001 slope goes to 0 correct?
Yeah
Take .99999 as limit and slope still goes to 0
Its my pleasure
