#Idk how to solve this
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∞
∑ (48n + 172n)
n = 1
@tacit mural Is this what you’re trying to say?
It becomes
∞
∑ 220n
n = 1
If that’s so.
But first I need you to confirm
So what would be the final answer?
Well do you know what it’s saying?
What all of this means
Yeah a little bit
∞
∑ 220n
n = 1
This notation is describing a sum, specifically you are summing 220n from n = 1 all the way to n = ∞, but something cannot “equal” infinite, but it can approach it, so we say n → ∞, basically what this is saying is:
220(1) + 220(2) + 220(3) + 220(4) + 220(5) + 220(6) + 220(7) + 220(8) + 220(9) + 220(10) + … + 220n, where n → ∞
Do you know what “divergence” and “convergence” means?
I do not lol
Thank you for your help
Ok convergence means that the sum of the terms converge (approach) a finite value such as 1, 6, -2, π, e, 2/7, basically any number.
Divergence means the sum of terms does not approach a finite value, and the sum either indefinitely oscillates or simply grows without bound (∞)
So if the sum converges , then there is a numerical answer, but if the sum does not converge then there isn’t really a numerical answer but we can say it is a divergent series, which lets us know the sum of the terms approach infinity, or don’t settle on one value — indefinitely oscillate (a series is the sum of a sequence of terms)
@tacit mural just based on intuition, do you think the sum converges or diverges?
Diverges…?
W teacher
Because as you keep adding the terms up, it approaches infinity, an example is
220(1) + 220(2) + 220(3) + 220(4) + 220(5) + 220(6) + 220(7) + 220(8) + 220(9) + 220(10) = 12,100
For the first 10 n, the sum is already above 12,000, and as you keep adding to it indefinitely, it does not settle on a value and keeps increasing indefinitely
So we say the sum equals infinity
Ok that makes sense
Do you know any calculus?
Because infinite series are primarily in the domain/study of calculus
So the answer is n → ∞?
No I don’t know any calculus I just saw this equation on the internet lol
Oh
Well if you’re interested I can help you with another problem similar if you’d like
Ok thank you for your help. You’re very informative