jovial raft
I believe it's called isosceles triangle. The sides are a, a and c.
The actual problem is to compare area surfaces of outer and inner circle. I just found the formula for small r = (a+b-c)/2. So I assume I'll need to find big R as well. Just marked some stuff on the graph and see some similar triangles but idk what to do from here.
agile treeBOT
hallow yoke
I believe it's called isosceles triangle. The sides are a, a and c.
The actual ...
i don't think your r is correct
imagine that the sides lengths of your isosceles triangles are rational such that the height perpendicular to the base c is irrational (i.e. √(a² - c² / 4)).
then the area should also be irrational.
however, if we apply the formula
area = inradius × semiperimeter
to your "inradius" r, you'll see that the "area" is always rational, which is false
misty hound
The radius of the outer circle 'R' would be the distance between the circumcentre of the triangle and any of the vertices.
jovial raft
Both small r and big R are radiuses. Small is for inner circle and big is for outer one. This pic only has one big R but I can use any of them.
misty hound
You can forget the small circle
jovial raft
I did already find the answer with another triangle so it will be easy to use this formula now. The formatting is quite bad but it works lmao
misty hound
Find the circumcentre of the triangle and find the distance between the circumcentre and any vertex
jovial raft
Here's an attempt using surface areas.
jovial raft
.solved