#Converges?

7 messages · Page 1 of 1 (latest)

fading bobcat
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In blue what I think the solution is.
In black what GPT says.

vestal thunderBOT
fading bobcat
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Both GPT and me get the solution right, I think

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Even that, am I making a mistake?
What theorem would you use?

thick crypt
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1/(1 + a^n) < 1/a^n So, sqrt(a^n)/(1 + a^n) < sqrt(a^n)/a^n = 1/sqrt(a^n) = 1/sqrt(a)^n So the sum converges if sqrt(a) < 1 which is the same as saying a < 1. Hence, your final condition is 0 <= a < 1

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Only theorems needed are direct comparison test and geometric serie convergence