help me wth is this

[cursive hearth]

thats just yap and thats not what mine is

[hollow mason]

For large n,

$ n! \sim \sqrt{2 \pi n}(\frac{n}{e}}^n $

[hollow mason]

google Stirling's approximation @cursive hearth, after plugging in this and taking the limit to infinity all the terms cancel out except pi

[maiden timber]

<@&268886789983436800> AI?

[dusty thicket]

this is completely and entirely unhelpful

[hollow mason]

u should check all his messages its kinda funny

[simple temple]

Yeah, I already saw him in other forums. Most probably AI since it has exactly the same form and does so many mistakes that AI tend to do

[cursive hearth]

is it a proven limit cuz approximation is not equal

if the limit is n! then ok

but if its not its just close

then no

[hollow mason]

the limit is equal at infinity

you can read more on the wikipedia page

[cursive hearth]

okay

i thought this would have smth to do with gamma idk why

cuz e and n!

literally gamma

[hollow mason]

you can derive that same formula using the gamma function too

so its not like it was a bad guess

[cursive hearth]

oh okay

oh rq

wth

even bigger tho

am i just dumb

or

forgetting

smth

😭

[hollow mason]

combine 1/(-2k) + 1/(2k-1) into one fraction by making common denominator

its equal

[cursive hearth]

oh okay im dumb

yeah

thx guys

how do u close a forum thread 😭

[simple temple]

!done

[brisk furnace]

If you are done with this channel, please mark your problem as solved by typing .close

[cursive hearth]

.close