Trig

[white prairie]

Is this right for y=cos(x+pie/2)*2 full cycle iff not can someone answer pls

[real plank]

is this what you are asking?

ohhh multiply by 2

that is not correct

[white prairie]

No this

[real plank]

it is not correct

[white prairie]

How do I fix it

[real plank]

try and graph cos(x+pi/2) and then shift it upwards by 2

[white prairie]

I don’t want to rush you but this assignment is already late is there any way you can just solve it for me or no

[real plank]

https://www.desmos.com/calculator/krhdcxlcsb

[white prairie]

the desmos doesnt graph all the points

[real plank]

wdym

[white prairie]

like i need to have those points on my x axis

[real plank]

-pi/2: y=3

0: y=2
pi/2: y=1
pi: y=2
3pi/2: y=3

[white prairie]

So is this right so far

like this?

@real plank sorry for rush but my teacher gave me 15 minutes on assignment and i didnt know till like 20 minutes ago so im already late

its hard to explain

[royal obsidian]

Okay

So you know how

Cos(x+pi/2) denotes a shift to the left, right?

?

[white prairie]

yeah

[royal obsidian]

So it would shift pi/2

To the left

Your diagram indicates that it’s just a normal cos graph not shifted

Like you know how cos is (0,1) when you start out right

(In this case it’s 0,2 cause the amplitude)

This right here as you denoted is 2 cos(x)

You need to shift the graph pi/2 to the left

[royal obsidian]

This one seems to be accurate

(Cause it’s shifted pi/2 to the left)

[white prairie]

is this correct

[half gulch]

Here you go, I’m not sure if this helps, but here’s how to change the Desmos axis settings to get it in terms of pi

[white prairie]

this is the correct answer i believe

[half gulch]

Yeah this one is correct, good job 👍👍

[white prairie]

ok thank you

[half gulch]

Is that all you need help with?