Integral Calculus Problem

[fossil igloo]

f(0)>g(0) and f(3)>g(3), so you find area by integrating upper(larger value) cruve - the lower curve
so integrate according to the formula given to you
f(x)-g(x) = 2x^2 - 4x + 4

integrate that with respect to dx from 0 to 3
giving area(x) = 2/3 x^3 - 4/2 x^2 + 4x
now area = area(3) - area(0)
so area = (18-18+12) - (0-0+0) = 12 sq units

[iron parcel]

Thanks bud appreciate it

It looks correct, the AI gives me a similar solution. Also 12 sq units

Oh sorry I deleted it

This was the problem

Just in case anyone has a similar one

[urban raft]

A and b are bounds?

[fossil igloo]

yep