#help finding displacement over time equation

42 messages · Page 1 of 1 (latest)

kindred cypress
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A particle that at the instant f = 0 is at a point A, travels in a straight line with constant speed of unknown module v. When a time T elapses the particle passes through a point B that is at a distance d from A.

a) Find v = v (d, T)

b) Give two expressions for the position of the particle as a function of time, one considering a coordinate system with origin in A and another considering a coordinate system with origin in B, and graph them.

floral kelpBOT
kindred cypress
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guys I did a) v = d/T, but how do I do b)??

cloud meteor
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assume displacement in x axis

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since velocity is constant, there no acceleration

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so velocity is also in the same positive x axis

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ig for point A at origin, x=vt is direct

kindred cypress
kindred cypress
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in my teachers notation

cloud meteor
kindred cypress
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how does this graph work?

cloud meteor
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since vel is ocnstant

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x = vt, i.e linear graph with slope = v

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also, for A at origin, t=0, x=0

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do the same for b

kindred cypress
kindred cypress
kindred cypress
kindred cypress
cloud meteor
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x= vt + k

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at t=0

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object is at A

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which is d distance behind B

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B is origin

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so x = -d

kindred cypress
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what about the frigging graph

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oh oh, got it

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the graph just indicates A as origin, after T time passes they meet

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and A to B is d displacement

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then second graph

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is B in origin

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because we chose A -> B frame of reference (+)

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so displacement B to A is -d

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and graph when B is at origin they meet after T time passes

kindred cypress
cloud meteor
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aah sorry, my pc got shut down

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and sorry i coulnt complete the explanation perfectly

kindred cypress
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I appreciate the help tho

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.solved