#Help Integration | PART C Question Issue
20 messages ยท Page 1 of 1 (latest)
f''(t) = t^3 - (8/15)t^(5/2) + Ct + D
[t^3 - (8/15)t^(5/2) + Ct + D] dt
t^3 dt = t^4/4
-(8/15)t^(5/2) dt = -(16/105)t^(7/2)
Ct dt = (C/2)t
dt = Dt
f(t) = t^4/4 - (16/105)t^(7/2) + (C/2) + Dt + E
Ct integrates to c/2 t^2
Still no
?
@maiden monolith you take the power to t^2 but that's not it
<@&286206848099549185>
still not?
then what?
didn't work
lemme check again
I entered:
t^4/4 - (16/105)t^(7/2) + (C/2)t^2 + Dt + E
It worked, can you send a picture of the workings because I want to see where I messed up for the t^2
in f'(t), the term is Ct
for f(t), integrate it, it forms to (c/2) t^2
๐๐๐๐ ๐๐ข๐ฅ๐ฅ๐๐ซ ๐๐