#Need help with this problem

9 messages · Page 1 of 1 (latest)

lean basalt
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I don't understand how to do this problem, the solution is quite vague

charred blazeBOT
spark night
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expand it and transform it into eqn of parabola

thin mica
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What they mean by "$x = \frac{1}{2} (\alpha + \beta)$" is the axis of symmetry", is that when you look at the plot of $f(x)$, then the graph is going to be reflectionally symmetric about that line.

storm spearBOT
thin mica
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so then the question is, how do you mathematically describe the idea of "refectionally symmetric"?

spark night
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and without a parabolic exuation, how will u prove it?

thin mica
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you don't need to convert it into parabolic form, I claim that you can prove both (a) and (b) just by looking at f in its original form, f(x) = a(x-a)(x-b)