So I'm a high school student studying high school and college level calculus at once and I have been able to solve every integral problem I've come across up until I've come across this problem in Hebrew: prove that if m and n are natural numbers then the following equation holds true, tip: don't calculate, just integrate by substitution.
#Help in an integration proof
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**Hint: ** make the change of variable , ||t=1-x||
trigonometria
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This is just for the laughs, I recommend using the first approach
I tried substituting t for 1-x I still get stuck with the problem of exponentiation because of the constants m and n
$$\int_0^1x^m(1-x)^n \space dx\stackrel{u=1-x}{=}\int_1^0(1-u)^mu^n(-1)du$$ $$=\int_0^1(1-u)^mu^ndu=\int_0^1x^n(1-x)^mdx$$
trigonometria
directly use kings property
ππππ ππ’π₯π₯ππ« ππ
here a=0, b=1, so proven by identity
I'd argue that you cannot prove king's rule using king's rule.
actually, its an identity
and it can be proven by symmetricity of graph
Something seems missing
I can see where you're going with the first three equations
But the way you connected the fourth one seems unclear
You might've substituted something incorrectly
$\int_a^b f(x) dx=\int_a^b f(u)du$
trigonometria
x is just a variable so we can change it as we wish
Yes but how are the first three equations, of course all equal to one another, equal to the fourth one
As long as u=1-x the equation remains unchanged
i just changed u for** x** .
I used king's property and it turned out to be a really reliable method
It's possible to change the value of a substitution variable?
yes it is just a dummy variable no real "information" is stored
that is only beacuse it is a definite integral though.
because the limits of integration change according to our variable any time we substitute
ye it is
so letting x=u at the end does nothing
Thank you guys so much