Pre-Calc: Rate of Change

[hazy holly]

Hey guys, I have about 9 questions on this homework I need help with. Here's the first one. 😔 Also we only got 3 tries per question and I've basically maxed them all out, so I'm desperate.

[pallid path]

Average rate of change over and interval can be calculated using

$\frac{f(x_1)-f(x_0)}{x_1-x_0}$

where x0 and x1 are the endpoints of the interval

Equivalently the average rate of change is the slope of the line passing through (x0,f(x0)) and (x1,f(x1))

[zealous flint]

purururuuriuruin

[hazy holly]

so just 4.9-2.9/8-2.2
?

cause i think i tried those and it said incorrect

[pallid path]

The endpoints are x=0 and x=8

[hazy holly]

ohh so 0.25?

[pallid path]

Hmm how did you get that

[hazy holly]

4.9-2.9/8-0

isnt it essentially just y2-y1/x2-x1?

[pallid path]

Yeah but y2=2.9 and y1=4.9 do not correspond to the function values at x2=8 and x1=0

[hazy holly]

ohh i see what youre trying to say

[pallid path]

You are looking at this (I think)

[hazy holly]

yes hahah

[pallid path]

But this is the average rate of change on the interval 2.2 < x < 6.1

[hazy holly]

so then i assume it should be 0-0/8-0??

[pallid path]

Yeah

[hazy holly]

got you, i was looking at it wrong LOL

so just 0?

[pallid path]

Yeah

[hazy holly]

ok cool thank you!