#Finding Volume of a solid
28 messages · Page 1 of 1 (latest)
u-sub
u = 2x²
du = 4x dx
what happens with x
also what happens with your bounds
x/x cancels
your lower bound 0 plug that into u = 2x² then your new lower bound is also 0
your upper bound sqrt(pi/2) plug that into u = 2x² then your new upper bound is... ?
yes
and no
yes that
first tell me the upper bound
in terms of u...
...
just plug it in
2(sqrt(pi/2))²
yes
so this integral transforms into that
can you help me with a math problem