#Physics. Heat exchange

31 messages · Page 1 of 1 (latest)

pastel osprey
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Physics. Heat exchange. Why is the specific heat of aluminum positive but not negative? I got ≈ -969.2 But the answers say that there will be 969.2. We get the equation Q given = Q obtained. It turned out that Q is given = 6300 but Q obtained = -6.5 * (-969,2) = 6299.8 ≈ 6300. So the left and right sides are equal, then why should the answer be positive and not negatively?

dreamy auroraBOT
proven bear
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Also, why 6.5 instead of 65?

pastel osprey
proven bear
pastel osprey
proven bear
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Either way: The temperature difference is -65, but if you're taking signs into account, the actual equality is that Qgiven = - Qobtained

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Their modulus is the same, which is what the sign-less formulation is getting at, but what the equation really represents is that there's no variation of energy if you consider the entire system.

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The variation of energy (Qgiven+ Qobtained) must be 0.

pastel osprey
proven bear
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Qgiven = Qobtained is only true if you don't consider the sign.

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If you do, then Qgiven = -Qobtained is correct.

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Underlying idea being that the total change in energy is 0, and it can be calculated as the sum of all individual changes of energy.

pastel osprey
proven bear
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Yeah.

pastel osprey
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Ok, thanks

pastel osprey
proven bear
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No, you'll get 969.2, which is the correct answer.

pastel osprey
proven bear
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You said you were originally getting a negative result, didn't you?

pastel osprey
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Yes

pastel osprey
proven bear
ionic topaz
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Or this

ionic topaz
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c >0