Beginner Calculus

[loud zodiac]

for the first one

g(2) is what, then plug that inito the x's for f(x)

[ancient furnace]

i haven't done math in years

i'm sorry

[loud zodiac]

okay

do you know what g(x) is

[ancient furnace]

yeah

i just plug 2 into the xs right

[loud zodiac]

ye

it.. might be easier to throw f(g(x) cause.. sqrt2 is annotying

[ancient furnace]

i get the first sentence then get confused at t =

[ancient furnace]

so i just solve f(g(2)) right

[loud zodiac]

ye

which gives you Q1

[ancient furnace]

what does the t = 5sin^2 mean

[loud zodiac]

it would be another number, Q is your variable

[ancient furnace]

sorry i was on a phone call

okay so i'm trying to i'm trying to solve all the variables right

i got g(2) = 2.07

and q1 = 2.71

where would i go from here i'm not sure what to do with the information q = ln(3 + |q1|) and t = 5sin^2(100Q)

@loud zodiac

[swift wind]

Do you know what sin means

[ancient furnace]

ohhh would i solve ln(3 + 2.71)

[ancient furnace]

not really, it's on my calc

i swear i haven't done math in years

[swift wind]

You don’t know what sin(x) is?

[ancient furnace]

not really

i always used a calculator fore it

for

[swift wind]

Oh.. well sin is a function

Have you ever taken trigonometry

[ancient furnace]

like 5-7 years ago

[swift wind]

Is what you’re showing homework?

or are you trying to just solve it

[ancient furnace]

kind of like homework

it's not graded but you have to send something to show you know it

so i'm trying to learn it

[ancient furnace]

how would i go on with my question

i solved q1

how would i solve ln(3 + 2.71)

[swift wind]

Well you’re missing a lot of background information

ln is a function aswell

Do you know what a function is

[ancient furnace]

yeah

ln is linear right

or log

one of them

[swift wind]

It’s the natural logarithm

ln(x) is just e^a = x
where e is a constant, approximately 2.718281828

so ln(2) is e^a = 2

It essentially asks what can you raise e by, in order to get 2

[ancient furnace]

i thought it was just plugging it all into the calculator

[swift wind]

ln(3 + 2.71) is just ln(5.71)

[ancient furnace]

which is 1.74 right

[swift wind]

I mean you can but it’s better to actually understand what it means

[swift wind]

Yes approximately

e^x = 5.71
where x ≈ 1.742

[ancient furnace]

then we solve t = 5sin^2(100q) with all the variables we solved?

how would i plug that into my calculator

[swift wind]

Hold on did you get Q1

[ancient furnace]

yeah

q1 = 2.71

[swift wind]

If Q is supposedly 2.71 (taking your word for it)

T = 5sin^2(100Q)
5sin^2(100 • 2.71)
5sin^2(271)

[swift wind]

What calculator do you even have

[ancient furnace]

ti-36x pro

it won't let me do 5sin^2

it's just doing 5sin(

[swift wind]

sin^2(x) = sin(x)^2

It’s just written like that

same with ln^2(x)

[loud zodiac]

t=5sin^2(100Q)

dont forget the last bit

[ancient furnace]

so it'd be the same as 5sin(271)^2?

so i got 4.99