#Combination
138 messages · Page 1 of 1 (latest)
,rotate
which questions
11-18😿
Well… hehehe none😿
Combination🫶🏻
alright, in combinatorics you have two main questions:
- do we care about the order in which the members are chosen?
- can we have repeated choices?
answer these 2 questions
why are you just giving the answer
🗿probably not used to helping
.
How’d you get that? I don’t even know how to solve it😿
It’s 7 chosoe 4
💀 💀 I thought i sent an image on the process but its not sending
I'm trying to explain 
some fruit one sent
It’s 7 choose 4
im not that braindead i promise🙏 😂
WHATTTTT wait so what’s the answer in number 11?😿😿😿
The same way you would've solved 16, no?
She doesn’t know how to solve them
in this case its7
oh so 11 to 18?
Yeah
r is the size of the "group" you are making
I think in combi, we don't need to care for the order. And we couldn't have any repeated choiches with same member like (a,b) = (b,a)
She needs help solving them as she’s lost
depends
Then how did u do 16
hence the question
here lemme start over
Combinatorics
but there's too many ppl here
I apologize in advance for stressing yall all out🙏
She probably just need a refresher
I know 💀 she needs help with the process and the formula
Ok so theres 2 variables to worry about here, "n" and "r"
"n" is the total amount of options in the equation
In #11 the "n" would be 7
"r" is the size of the desired group
In #11 the "r" would be 4
Then plug them in
7!
(7!-4!) * 4!
Then punch that in
@glacial matrix
It should be 7!/4!(3!)
Ohhhhh OKAY OKAYYY I get it
Mhm
But how do you get the final answer
Or like how do you solve the whole thing
What am I saying😭🙏
do you know what ! means?
Factorial 😏
just giving the formula is useless if you don't explain when to use it and why it works
@graceful kayak let’s go back to discussy
Sadly agree
sorry lol, i tried my best haha, gl tho!!
But don’t worry I understand the formula
It’s just that I don’t understand how to solve the whole thing
@glacial matrix say each of our 7 had a number, and you chose a committee by calling out one by one the number of every person on the committee, say 1,3,4,7
would calling out 3,1,7,4 be a different committee?
I’m not sure about my answer but maybe yeah since it’s in different orders
but is it a different committee?
No?🙏
it's still the same members, right?
Yeah yeah just unordered
a committee doesn't have an order of members
if you chose 1 and then 3 you'd still end up with the same committee as if you chose 3 and 1, right?
does that make sense?
they end up in the same meeting room regardless
Yeahhh
great, so question 1 is answered, we don't care about order
as in, 1,3,4,7 is the same as choosing 7,3,4,1
now, can we have any repeats
So what do I put?😭
patience
OHHH WAIT OKIEE
I want to explain the logic behind this
as in, is 1,1,3,4 a valid choice?
No
correct
Yay
so we cannot have any repeats
Mhmmmmm
for this kind of question, we have the "choose" function (often called the binomial function) which answers the question how many ways can you choose groups of size n out of a bigger group of size m without repeats and without caring about order
for example, ${5 \binom 3}$ (also sometimes written $^5C_3$ and is said out loud as "5 choose 3") is the amount of ways to choose groups of 3 ppl out of a bigger group of 5 without caring about order and without repeats
ξor.
for this kind of question, we have the "choose" function (often called the binomial function) which answers the question how many ways can you choose groups of size n out of a bigger group of size m without repeats and without caring about order
for example, ${5 \binom 3}$ (also sometimes written $^5C_3$ and is said out loud as "5 choose 3") is the amount of ways to choose groups of 3 ppl out of a bigger group of 5 without caring about order and without repeats
```Compilation error:```! Argument of \@genfrac has an extra }.
<inserted text>
\par
l.61 for example, ${5 \binom 3}
$ (also sometimes written $^5C_3$ and is said...
I've run across a `}' that doesn't seem to match anything.
For example, `\def\a#1{...}' and `\a}' would produce
this error. If you simply proceed now, the `\par' that
I've just inserted will cause me to report a runaway
argument that might be the root of the problem. But if
your `}' was spurious, just type `2' and it will go away.```
,w 7c4
yes
Yayyy
but do you understand why we use the choose?
Yupperssss
you should've derived it in class
Yup yup I will if they call me HHAAHHAHAHA
explaining why it works is a bit over my ability on discord
ikr
for ease of access
4845 ways
show your workings
None anymore heheh thank youuuuu