DIVISIBILITY | NUMBER THEORY | Mathematics | Page 1

frigid hemlockBOT Jan 13, 2025, 7:08 PM

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errant maple Jan 13, 2025, 7:31 PM

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!status

frigid hemlockBOT Jan 13, 2025, 7:31 PM

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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

honest pagoda Jan 13, 2025, 8:06 PM

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I know that (a^n -1) = (a-1)(a^(n-1) + a^(n-2)+ ... + a + 1)

timid terrace Jan 13, 2025, 8:23 PM

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honest pagoda I know that (a^n -1) = (a-1)(a^(n-1) + a^(n-2)+ ... + a + 1)

,texsp
Hint:
(\) Let ( \gcd(m,n) \eqqcolon b. \ ) Then for some ( x,y \in \mbb{Z} ) you have
( m = bx ) and ( n = by. )

#DIVISIBILITY | NUMBER THEORY