#Is this right?

24 messages · Page 1 of 1 (latest)

dull sand
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Just wondering if this is correct

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mossy impBOT
rugged chasm
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8-5 is 3.

dull sand
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Oh shit

dull sand
rugged chasm
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You cant cancel numerator and denominators in subtraction.

dull sand
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Oh

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Can you when adding or is it only when multiplying and dividing?

rugged chasm
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I think you need to simplify your view on negative numbers.
A "negative number" is simoly just a number. Think of 5 - 3 as simply the addition of 5 and - 3 (5 + (-3)).

rugged chasm
dull sand
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Alr and one more thing, now that I fixed the mistake on the other question it’s right now?

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rugged chasm
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Whered the - of -1/6 go?

fierce shard
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You would be better off simplifying $\frac{3}{6} = \frac{1}{2}$

And then doing the $\frac{1}{2}\times \frac{1}{2} = \frac{1}{4}$

So you get $-\frac{1}{6} \div \frac{1}{4} = -\frac{1}{6} \times \frac{4}{1} = -\frac{4}{6}=-\frac{2}{3}$

slate wolfBOT
dull sand
dull sand
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Wait that means I still got it wrong

fierce shard
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yes, because you changed $a \div (b \times c)$ into $a \times \frac{1}{b} \times c$ instead of $a \times \frac{1}{bc}$

slate wolfBOT
dull sand
fierce shard
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You are dividing by the whole term $\left(-\frac{5}{6}+\frac{4}{3}\right)\left(-\frac{5}{6}+\frac{4}{3}\right)$, so you need to simplify it first, all the way to $\frac{1}{4}$, before doing the division.

slate wolfBOT
fierce shard
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You have $a \div b$ where $b$ is the messy term that simplifies to $\frac{1}{4}$.

You have simplified as far as $b = \frac{3}{6} \times \frac{3}{6}$.

If you divide at that point, you need $-\frac{1}{6} \div \left(\frac{3}{6} \times \frac{3}{6}\right) = -\frac{1}{6} \times \cfrac{1}{\frac{3}{6} \times \frac{3}{6}}$

... which is much messier than simplifying the $b$ term first.