#Smallest Circle to Fit All Six U.S. Coins: A Geometric Challenge

33 messages · Page 1 of 1 (latest)

gusty ploverBOT
fluid moss
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add them

twilit mica
fluid moss
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orientation is irrelevant

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the diameter will remain the same

twilit mica
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well yes but just adding the diameters would mean u created a circle with the diameter of the sum of all the coins

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which wouldnt be the smallest for sure

fluid moss
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also why tf is there a dollar bill there

twilit mica
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dollar coin

fluid moss
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ahh

twilit mica
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this is a tricky question tho and im not sure how to solve it

fluid moss
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so uh

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the longest possible diameter would be the sum of the coins' diameters, right?

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could you decrease the length by slowly stacking the coins height wise?

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it'd be parabolic

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i think

twilit mica
twilit mica
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because thats the largest circle that those coins will fit in

fluid moss
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"Note that the coins must be arranged such that their edges are tangent to the circle, meaning the central space cannot will be left empty."

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doesn't this uh

twilit mica
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ah i see

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well i mean we could have all the coins resting tangent to the infinite circle

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sure thats kinda paradoxical

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but it more goes to represent that even for large circles, the coins can still rest at the edge

fluid moss
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I'm thinking

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making a square with the coins

twilit mica
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thats a good idea

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i suppose what we have to do is try and wrap the coins as tightly as possible

fluid moss
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Yeah

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probably like stack them into the z direction

glad ether
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Find the area of six coins the multiple them by 6, if coins are like base. But if coins are perpendicular then there are lots of factors for example orientation of coins. According to the information given by you I think the first one is good