#if x divisible by 32 and by 12 , is x divisible by 8 ?
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what do you think
8 = 2^3
Remember that if x is divisible by all the factors of a number, then it's divisible by that number
32 is 8*4, that’s the only thing we need to know
different denominators of the same numerator don’t need to have the same factor
18 divisible by 9 and 2, for instance
i get why x is divisible by 8, given x divisible by 32
i dont get how x is divisible by 8, given x divisible by both 32 and 12.
32 = 22222 , how do i recreate 12 with these factors ?
2^5
Consider this
If x is divisible by both 32 and 12, it must be divisible by 2^5 and 2^2 * 3
That means that x must at the very least be 2^5 * 3
Any number that is divisible by 32 and 12 must also be divisible by 2^5 * 3
And since 8 is a factor of this prime factorization
We know now that if a number is divisible by 32 and 12 then it is divisible by 8
so we take the lcm of the two factors ?
and see if we can create 8 out of the lcm ?
Yes
If a number is divisible by two numbers then it's divisible by their lcm
how would the question differ if i had to use gcd ?
And if those two numbers are coprime then their lcm is just their product
it is cuz 32 is divisible by 8
ok, this is cool
co prime is when they only have the number 1 in common ?
when do i use gcd in such ocasions ? gcd of 32 and 12 would be 2^2*3 right ? or just 2^2 ?
Not sure gcd really comes up here
But the gcd of 32 and 12 is 4
15 is divisible by 3 and 5 but 3 and 5 are mutually (and actually) prime. it doesn't matter than 12 is not divisible by 8 the fact that a known factor of x is divisible by 8 implies that 8 is also a factor of x.
@rough atlas so based on @wet hill , if x divisible by x1,x2,x3 then if we know that 1 out of the x's numbers is divisible by 8 means that 8 is also divisible by x ?
like sort of a tree thing
with parents and childs
whats the point of finding gcd and lcm ? where do these come in handy ?
no it doesnt
32 is divisible by 8 but 8 is not divisible by 32
im confused