#Logarithms Question Help
27 messages · Page 1 of 1 (latest)
first of all, do you know the identity log_a(b) = log(b)/log(a) ?
loga-logb=loga/logb right?
no, that's not right
$\log_a(b) = \frac{\log (b)}{\log (a)}$, and $\log (a) - \log(b) = \log (\frac{a}{b})$
HChan
don't get them mixed up
Change base is the first one
Yeah i know it
okay, so then
$\log_x y + \log_y x = \frac{\log y}{\log x} + \frac{\log x}{\log y}$
HChan
ok
i did not look at it this way
now I can rewrite the question as this:
Given $\begin{cases}
X + Y = \frac{5}{2} \
XY = 1
\end{cases}$,
what is $\frac{X}{Y} + \frac{Y}{X}$?
HChan
now can you solve this
Yes common denominator then you will x^2+y^2/xy
then xy is 1
and x^2+y^2 = (x+y)^2-2xy
there you go