#Algebra
4 messages · Page 1 of 1 (latest)
use the standard inequality (x+y+z)^2>=3(xy+yz+zx) with x=1/a, y=1/b, z=1/c.
4 messages · Page 1 of 1 (latest)
a,b and c are three positive real numbers with : ab+bc+ca =1 prove that :
use the standard inequality (x+y+z)^2>=3(xy+yz+zx) with x=1/a, y=1/b, z=1/c.