#Find the value
6 messages · Page 1 of 1 (latest)
x^4+324=f(x)f(x+6), where f(x)=x^2-6x+18. So it equals f(10)f(16)...f(64)/(f(4)f(10)...f(58)). Everything cancels out leaving only f(64)/f(4)=373.
Pardon me how did u get x²-6x+18 ? Thx
I factorized x⁴+324 by completing a square: x⁴+324=(x²)²+2 * 18x²+18²-2 * 18x²=(x²+18)²-(6x)².
Ok