#Why was the 4^x being multiplied for all sides? Is it a strategy?
pale flintBOT
pallid zodiac
<@&286206848099549185>
hot bolt
<@&286206848099549185>
It’s a quadratic in disguise
Let u=4^x
And u have a quadratic in terms of u
pallid zodiac
For which reason?
hot bolt
For which reason?
That’s basics algebraic laws ?
pallid zodiac
I'm missing out a lot of laws
Idk why
I'm do advanced function and still missing out some laws
pallid zodiac
Yh, we did them last year but not all of them. I also missed almost the whole semester because of my sickness
empty falcon
\begin{align*} 4^x +6(4^{-x}) &= 5 \ 4^x +\frac{6}{4^x} &= 5 \qquad \text{using index laws} \ 4^x\times 4^x +\frac{6}{4^x}\times 4^x &= 5\times 4^x \qquad \text{on multiplying by $4^x$} \ \left(4^x\right)^2 +6\times \frac{4^x}{4^x} &= 5\times 4^x \ \left(4^x\right)^2 +6 &= 5\times 4^x \qquad \text{as $\frac{4^x}{4^x} = 1$} \ u^2 + 6 &= 5u \qquad \text{on substituting $u=4^x$} \end{align*}
lyric veldtBOT
Jay
pallid zodiac
I still need help for something if you guys aren't busy
pallid zodiac
\begin{align*} 4^x +6(4^{-x}) &= 5 \\ 4^x +\frac{6}{4^x} &= 5 \qquad \text{using...
Tbh, I didn't even know that law, I really need to do a catch up
@empty falcon I got another question related to trig ratio for that question, I had to draw an angle and determine the other trig ratios
