#I don't understand what to do. (angle measures & side proportions)
39 messages · Page 1 of 1 (latest)
For the side proportions, it is literally asking you to find the
given ratios as simplified fractions. For example::
\begin{align*} \frac{AC}{ZX} &= \frac{10}{7.5} \ &= \frac{10}{7.5} \times \frac{2}{2} \ &= \frac{20}{15} \ &= \frac{4}{3} \end{align*}
Jay
The angle $\angle{VXZ}$ can be found using the fact that the angle sum of a triangle is $180^\circ$
Jay
In $\Delta VXZ$, we know that $\angle{VXZ} + \angle{XZV} + \angle{ZVX} = 180^\circ$
as the angle sum of any triangle is $180^\circ$, yes?
And we know that $\angle{XZV} = 27^\circ$ and that $\angle{ZVX} = 22^\circ$.
You can put these two pieces of information into the above equation
which will now have a single unknown, $\angle{VXZ}$, and you can
solve the equation to find the size of this angle.
Jay
I expected that they would be the same... what does this mean about the relationship between the two triangles? Hw does this help you to solve the rest of the question?
so 180 minus the two other angles
to find the unknown
wait no
this is what i have
im unsure if i have CAF and CFA swapped incorrectly though
The ratios tell you that AC corresponds to ZX and AF corresponds to ... ?
eachother?
Because the angle between AC and AF will correspond to the angle between ZX and whichever side corresponds to AF
The first ratio was AC / ZX, meaning that this pair of sides is corresponding
Which ratio has AF in it? hence, which side corresponds to AF?
VZ?
Yes
So, the angle you want is between AC and AF... so, the corresponding angle is between ...?
CAF?
CAF is the angle you want, yes... it is between CA and AF... the sides corresponding to CA and AF in triangle VXZ are ... ?
AC - ZX
And AF corresponds to VZ, you said so above
Yes