geometry

[zealous trout]

4 root 3

[pale ledge]

alr thx

[sick crystal]

We know that angle C is 30 degrees and we have a right angled triangle. We can apply SOH CAH TOA and solve for the length AC

[pale ledge]

yeah realized that now

[pale ledge]

hey Ive got another question

[sick crystal]

It would be the sine rule (for non-right angled triangles)

[pale ledge]

alr thanks

[sick crystal]

This is the reasoning behind it

We know in the question the angle B (127 degrees) and the corresponding side B (34). We know the corresponding side of A (18) but we dont know the angle. So, we can subsitude everything into the sine rule and solve the angle A (capital = angle, lowecase = side)

[pale ledge]

yeah i can understand that just didnt know to use it from the pic

[pale ledge]

i dont get this tho is the problem wrong?

because it saids s

[sick crystal]

Im gonna guess from first look that the s should cancel out

I think its d

We can apply TOA in this example.

TanA = opposite / adjacent.

We know that the opposite side is s * sqrt(3) but we don't know adjacent. To calculate the adjacent, we need to use Pythagoras' theorem

So we take square root of (2s)^2 - (s(sqrt(3))^2 = s^2. Taking the sqrt(s^2) simply equals to s.

So, the adjacent is equal to s. Because we have found the adjacent, we can just sub into the TOA experssion

We get, TanA = [s * sqrt(3)] / s. and this just equals to sqrt(3) because the s values cancel

[pale ledge]

OHHHH YEAHHH HUH HOW DID I NOT SEE THAT

[sick crystal]

You got it?

[pale ledge]

yeah thanks dude