Slant Asymptote Problem - Calc 1

[shut garnet]

maybe find limit as derivative approach +- infinity?

for slope of slant asymptote

[peak girder]

how come it would be the limit of the derivative? i was trying to do m=lim as x approaches inf f(x)/x but i was getting infinity as my answer so thats not right

[shut garnet]

its just alternative method that might be easier

[shut garnet]

im not sure if this works when the slant asymptote doesn't pass thru origin

actually it should nvm