#Can this be solved using u-sub instead of using the trig identity for cos(2x)?
wraith surgeBOT
dense tide
not in the traditional sense, at first glance
boreal vortex
But I can apply u to the inner function of the sqrt
and cancel out the sin(2x) no?
@dense tide
I tried this got the answer 3.33
3.133
Chatgpt got the same thing applying u sub
dense tide
oh wait I might
dense tide
I might've read the problem wrong, let me try it real quick
@boreal vortexyou do realize you have to use the chain rule when using that u sub right
earnest hearth
cant you just write 1+4cos^2 as 4sin^2
boreal vortex
cant you just write 1+4cos^2 as 4sin^2
Yeah but I don't think i'll remember the trig identity for that
on my midterm lmaooooo
that's why i'm asking if I can use u-sub instead
dense tide
that's why i'm asking if I can use u-sub instead
i dont believe so, because letting $u = 1+4cos^2(2x)$ yields $du = -16cos(2x)sin(2x)$
vestal ravineBOT
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dense tide
sorry, times dx
boreal vortex
how?
boreal vortex
OOOOHHHHHHHH
earnest hearth
you would have to use trig identity to solve this?
boreal vortex
when you take the derivative of a trig identity squared
or a trig identity to the power of anmtyhing
that happens
TYSM
earnest hearth
i dont see a way without the use of trig identity
boreal vortex
this solved my issue
dense tide
or a trig identity to the power of anmtyhing
any 2 or more functions