#Integral Triple

21 messages · Page 1 of 1 (latest)

stone vaporBOT
white wadi
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Is the first pic the hyperboloid function?

inner cipher
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the first pic is the formula of the lateral surface

white wadi
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How I always think about these integrals is by breaking it down into steps. Starting with the simplest

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You want to integrate for mass, so it's literally just $M=\int dm$. Then we need to know the bounds of $m$. The bounds are spatial ($dV$). So how do we related mass and volume? That's where density comes in. We know the density is constant in the hyperboloid cylinder, and 0 outside. Let the density constant be $\rho$. Then $dm=\rho dV$.

placid cosmosBOT
white wadi
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So the integral becomes $M=\iiint \rho dV$, bounded by the hyperboloid.

placid cosmosBOT
white wadi
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You are asked to integrate in cylindrical coordinates, which makes sense given the nice symmetry

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Do you remember $dV$ in cylindrical coordinates?

placid cosmosBOT
inner cipher
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we got a progress in a help channel

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got this

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we got this*

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is it right?

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in case it is

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im having trouble now calculating the moment of inertia respect to the axis y

white wadi
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the t and z bounds are correct. I need a second to verify the r bounds

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yeah the bounds are all correct