need help plz

[latent jay]

is the answer all of them?

[grim prawn]

Explain

[latent jay]

sure

for i) at x= -3 f'(x) corsses the x axis from negative to postive

which indicates that f(x) indeed has a local minimum at x= -3

for ii) at x= 3, f'(x) has an open circle, which says its undefined , but f'(x) remains negatives

both before and after x=3

which means no sign change happened or anything

for iii) at x=1, f'(x) crosses the x- axis from positive to negative which indicated a local maximum for f(x0

so all of them would be true right?

or did i do something wrong?

[grim prawn]

but f(x) is continuous in x = 3

-|x| is also not differential in x = 0 but has local max in x = 0

[latent jay]

so ii is not true your saying?

[grim prawn]

yes

[grim prawn]

Is there a change of monotony?

Also recall for maximum it is sufficient f''(1) < 0, is that the case for f'?

[latent jay]

oh okay

its i only

thats true

correct?

[grim prawn]

yes

[latent jay]

i got a half mark

meaning theres another one thats true

its i) for sure thats true

but i believe theres another one as well

[grim prawn]

Then I'd say it's ii

[latent jay]

i and ii true right