#Triple integral with a transformation and then spherical coordinates
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teacher says the answer is 64pi/105 but i have no idea how he got there
bacc (unhelpful)
yes
jacobi
oh so youve already done the jacobian?
i was typing out an explanation of that but no worries if so : P
oh mb
yeah it's 144
alright, so now you just need the bounds for the integral then right?
its just, when you sub in, does the integral become 9u^2 * 36v^2 * 64z^2 ?
i think you meant for that z at the end to be a w, and if you did then yes exactly!
oh yeah w
how
because the integrand is just x^2 y^2 z^2 so that's just the product of our subs squared
okay cuz when i see problems online they just put in the jacobian and then say the integral is uvw and it made me incredibly confused
it shouldnt be this
why not?
oh am i wrong?
idk im confused
The substitution is supposed to remove the factors
but isn't x = 3u so when u sub u in for x you get (3u)^2?
so you can apply spherical coords
IT DOES???
but look at the denominator
you divide by 9
9/9 = 1
and so on
oh bruh i am stupod
nahh no worries lol you almost gave me a heart attack!
the integrand is a product of these
im in the middle of a heart attack
LOL we're good now
none of my answers match the answer key ๐ญ
so now that we have an integral in terms of u v and w, we just need to figure out the bounds right?
well you swap to spherical coords
yeah exactly
cuz the region is a sphere
so we do another "jacobian" but we really know what it is by heart now
and the bounds are 0 -> 2pi, 0 -> pi and 0->1
yup row^2 sin(phi) dpdphidtheta
and then with the integral in it with all the squares
times the 144
yeah, how do the squares simplify? so we converted our differentials to rho phi and theta, which means our squares will change too right?
(sorry im legit asking cause i dont have paper and my internet is really slow : P
,calc 144 * 3^2 * 6^2 * 8^2
Result:
2.985984e+6
that's where i thought it was 9u^2 * 36v^2 * 64w^2 so itd change to 9(rho * sin(phi) * cos(theta))^2 * 36 (rho * sin(phi) * sin(theta))^2 * 64(rho * cos(phi))^2
the last one should be cos phi right?
what was the jacobian again
144
of spherical coords
looks good then! so we have 9 * 36 * 64 * rho^6 * sin ^4 (phi) * cos (theta) ^2 * sin(theta) ^ 2 from the integrand, right?
times the jacboain we would then have 9 * 36 * 64 * rho^8 * sin ^5 (phi) * cos (theta) ^2 * sin(theta) ^ 2
yes
alright cool! oh and times the 144 from earlier, i forgot that
yup
,w 144 * Integrate[9(rho * sin(phi) * cos(theta))^2 * 36 (rho * sin(phi) * sin(theta))^2 * 64(rho * cos(phi))^2 * rho^2 sin(phi), {phi,0,pi}, {theta,0,2pi}, {rho,0,1}]
alright so now we have everything ready to go, did you have trouble integrating any of these variables in particular?
or was everything fine you just got a different answer? it seems like you get the idea, so it may be a small mistake somewhere in the math?
honestly i think the teacher might just be wrong
but he's been doing random stuff for the entire last five problems of the answer key
so i think he's just forgetting to actually sub in the (3u) instead of u
ty ๐ญ
ty ๐ซก
did you get this btw?
yeah something around that
,w Integrate[x^2y^2z^2, {x,-3,3}, {y, -6sqrt(1-x^2/9), 6sqrt(1-x^2/9)}, {z, -8sqrt(1-x^2/9-y^2/36), 8sqrt(1-x^2/9-y^2/36)}]
Could someone help me?๐ญ
dxdydz maybe try that too
,w Integrate[x^2y^2z^2, {z,-8,8}, {y, -6sqrt(1-z^2/64), 6sqrt(1-z^2/64)}, {x, -3sqrt(1-z^2/64-y^2/36), 3sqrt(1-z^2/64-y^2/36)}]
yea you can show this