#Triple integral with a transformation and then spherical coordinates

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thorny roost
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Does anyone know how to do #105?

shy sentinelBOT
thorny roost
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teacher says the answer is 64pi/105 but i have no idea how he got there

idle kettle
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Have you used the sub

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it's no coincidence

thin iglooBOT
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bacc (unhelpful)

thorny roost
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yes

idle kettle
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jacobi

crimson berry
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i was typing out an explanation of that but no worries if so : P

idle kettle
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oh mb

thorny roost
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yeah it's 144

crimson berry
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alright, so now you just need the bounds for the integral then right?

thorny roost
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its just, when you sub in, does the integral become 9u^2 * 36v^2 * 64z^2 ?

crimson berry
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i think you meant for that z at the end to be a w, and if you did then yes exactly!

thorny roost
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oh yeah w

crimson berry
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because the integrand is just x^2 y^2 z^2 so that's just the product of our subs squared

thorny roost
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okay cuz when i see problems online they just put in the jacobian and then say the integral is uvw and it made me incredibly confused

thorny roost
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why not?

crimson berry
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oh am i wrong?

thorny roost
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idk im confused

idle kettle
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The substitution is supposed to remove the factors

thorny roost
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but isn't x = 3u so when u sub u in for x you get (3u)^2?

idle kettle
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so you can apply spherical coords

thorny roost
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IT DOES???

idle kettle
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you divide by 9

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9/9 = 1

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and so on

thorny roost
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no for the regular integrand

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integral of x^2 * y^2 * w^2

idle kettle
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oh bruh i am stupod

crimson berry
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nahh no worries lol you almost gave me a heart attack!

idle kettle
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the integrand is a product of these

thorny roost
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im in the middle of a heart attack

crimson berry
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LOL we're good now

idle kettle
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yea

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mb sorry guys

thorny roost
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none of my answers match the answer key ๐Ÿ˜ญ

crimson berry
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so now that we have an integral in terms of u v and w, we just need to figure out the bounds right?

thorny roost
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well you swap to spherical coords

crimson berry
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yeah exactly

thorny roost
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cuz the region is a sphere

crimson berry
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so we do another "jacobian" but we really know what it is by heart now

thorny roost
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and the bounds are 0 -> 2pi, 0 -> pi and 0->1

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yup row^2 sin(phi) dpdphidtheta

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and then with the integral in it with all the squares

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times the 144

crimson berry
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yeah, how do the squares simplify? so we converted our differentials to rho phi and theta, which means our squares will change too right?

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(sorry im legit asking cause i dont have paper and my internet is really slow : P

idle kettle
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,calc 144 * 3^2 * 6^2 * 8^2

thin iglooBOT
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Result:

2.985984e+6
thorny roost
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that's where i thought it was 9u^2 * 36v^2 * 64w^2 so itd change to 9(rho * sin(phi) * cos(theta))^2 * 36 (rho * sin(phi) * sin(theta))^2 * 64(rho * cos(phi))^2

crimson berry
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the last one should be cos phi right?

thorny roost
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yes

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mis-write ๐Ÿ˜ญ

idle kettle
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what was the jacobian again

thorny roost
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144

idle kettle
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of spherical coords

thorny roost
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oh

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rho^2 sin(phi)

crimson berry
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looks good then! so we have 9 * 36 * 64 * rho^6 * sin ^4 (phi) * cos (theta) ^2 * sin(theta) ^ 2 from the integrand, right?

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times the jacboain we would then have 9 * 36 * 64 * rho^8 * sin ^5 (phi) * cos (theta) ^2 * sin(theta) ^ 2

thorny roost
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yes

crimson berry
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alright cool! oh and times the 144 from earlier, i forgot that

thorny roost
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yup

idle kettle
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,w 144 * Integrate[9(rho * sin(phi) * cos(theta))^2 * 36 (rho * sin(phi) * sin(theta))^2 * 64(rho * cos(phi))^2 * rho^2 sin(phi), {phi,0,pi}, {theta,0,2pi}, {rho,0,1}]

crimson berry
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alright so now we have everything ready to go, did you have trouble integrating any of these variables in particular?

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or was everything fine you just got a different answer? it seems like you get the idea, so it may be a small mistake somewhere in the math?

thorny roost
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honestly i think the teacher might just be wrong

crimson berry
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it does happen for sure ๐Ÿ˜

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in any case it seems like you understand the process

thorny roost
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but he's been doing random stuff for the entire last five problems of the answer key

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so i think he's just forgetting to actually sub in the (3u) instead of u

thorny roost
idle kettle
thorny roost
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yeah something around that

idle kettle
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,w Integrate[x^2y^2z^2, {x,-3,3}, {y, -6sqrt(1-x^2/9), 6sqrt(1-x^2/9)}, {z, -8sqrt(1-x^2/9-y^2/36), 8sqrt(1-x^2/9-y^2/36)}]

idle kettle
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yea I think your teacher is wrong

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cartesian got the same result

thorny roost
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okay that's good

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i was concerned

verbal ocean
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Could someone help me?๐Ÿ˜ญ

idle kettle
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dxdydz maybe try that too

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,w Integrate[x^2y^2z^2, {z,-8,8}, {y, -6sqrt(1-z^2/64), 6sqrt(1-z^2/64)}, {x, -3sqrt(1-z^2/64-y^2/36), 3sqrt(1-z^2/64-y^2/36)}]

idle kettle
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yea you can show this