Hello!! Currently revising for exams (rip) and trigs probably one of my weaker topics. The question I have is that I understand somewhat what this question is asking me, but I'm having a bit of trouble understanding the exact answers (such as why some are negative, or why it only includes a specific part), I'm up to part c and stuck
#Trigonometry, circular functions
13 messages · Page 1 of 1 (latest)
Find the solutions for $\sin{x}=\frac{1}{2}$ in the interval $x\in \left[ 0,2\pi \right]$ first.
Determine angles in the unit circle
solarunes
sin(θ− pi/3)=-1/2, the angle θ - pi/3
: \theta = \frac{11\pi}{6} + \frac{\pi}{3} = \frac{13\pi}{6} = \frac{2\pi}{6} + 2\pi = \frac
I'm still a bit confused, ive tried to do that but it says the angles are pi/3 and 3pi/2
as the answer for part c
and I'm not too sure on how that was acheived
hm thats odd, ykw its okay I'll ask my math teacher tmr but thank you!!