Finding Domain of a Inverse Function Problem | Mathematics | Page 1

odd kiln Nov 3, 2024, 3:23 PM

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I can’t figure out the right answer to part 2 when the limit isn’t specified, how do I solve when the answer can’t be infinity as one of the intervals??

hollow crescentBOT Nov 3, 2024, 3:23 PM

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queen kiln Nov 3, 2024, 3:30 PM

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5 to infinity is right just fix format when u enter it

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∞

crisp dew Nov 3, 2024, 3:35 PM

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likely just a website error, maybe ‘oo’ isnt seen as infinity

queen kiln Nov 3, 2024, 3:37 PM

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put x >= 5

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or x ≥ 5

odd kiln Nov 3, 2024, 3:41 PM

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queen kiln put x >= 5

My professor said it can’t be infinity so Also how is it x >= 5 if it says interval notation

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I have 1 attempted left so how to enter it

queen kiln Nov 3, 2024, 3:43 PM

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one moment

crisp dew Nov 3, 2024, 3:46 PM

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try putting it into a quadratic form then finding the range for which the discriminant >= 1

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it cannot be “[5…”because when you put x as 5, it gives a number more than 0, so there are definitely numbers below 5

queen kiln Nov 3, 2024, 3:54 PM

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so (−∞,∞)

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@crisp dew

odd kiln Nov 3, 2024, 3:55 PM

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crisp dew

I don't understand so, it values out to all the values - 2/ 7 and above

crisp dew Nov 3, 2024, 3:55 PM

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x < 3.58…, x > 6.41….

queen kiln Nov 3, 2024, 3:56 PM

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no thats not right

odd kiln Nov 3, 2024, 3:56 PM

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queen kiln so (−∞,∞)

It can't be infinity i tried before

crisp dew Nov 3, 2024, 3:56 PM

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crisp dew

unless I plugged it in wrong

queen kiln Nov 3, 2024, 3:57 PM

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((x-5)^{2}-2)/7

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you said your professor said it cannot be infinity?

crisp dew Nov 3, 2024, 3:59 PM

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queen kiln ((x-5)^{2}-2)/7

stilll, plugging those numbers into that formula gets me 0

odd kiln Nov 3, 2024, 4:02 PM

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queen kiln you said your professor said it cannot be infinity?

He addressed it because past students represented outputs with infinity sometimes

crisp dew Nov 3, 2024, 4:03 PM

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i assume he meant that writing [5, ∞] would be wrong

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you can write infinity in domains, but it has to be [5, ∞)

queen kiln Nov 3, 2024, 4:03 PM

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i agree

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i still think your math input was probably wrong

odd kiln Nov 3, 2024, 4:04 PM

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I'll entering that notation with that symbol

queen kiln Nov 3, 2024, 4:04 PM

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is there not a math input feature

crisp dew Nov 3, 2024, 4:05 PM

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crisp dew x < 3.58…, x > 6.41….

try it anyway, if not try this

odd kiln Nov 3, 2024, 4:05 PM

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"[5, ∞)"

crisp dew Nov 3, 2024, 4:06 PM

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ye, ney?

odd kiln Nov 3, 2024, 4:06 PM

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odd kiln Nov 3, 2024, 4:07 PM

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odd kiln "[5, ∞)"

failed

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didn't work

crisp dew Nov 3, 2024, 4:08 PM

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aight so its gotta be the other one

queen kiln Nov 3, 2024, 4:08 PM

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i think that was his last attempt

crisp dew Nov 3, 2024, 4:08 PM

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no idea what fraction to get those two numbers but

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wait shit?

odd kiln Nov 3, 2024, 4:08 PM

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i can still try, it just won't add credit

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it's fine it's 9.5/10

crisp dew Nov 3, 2024, 4:08 PM

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may aswell try

odd kiln Nov 3, 2024, 4:09 PM

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i just wanna know

crisp dew Nov 3, 2024, 4:09 PM

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queen kiln ((x-5)^{2}-2)/7

(x^2 -10x + 23) / 7

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a = 1/7, b = -10/7, c = 23/7

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discriminant = sqrt(-10/7^2 - 4(1/7)(23/7))

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put 0 = discriminat, find the two values for x

odd kiln Nov 3, 2024, 4:14 PM

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crisp dew may aswell try

so 8/49?

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and the other?

crisp dew Nov 3, 2024, 4:14 PM

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no i dont think so

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that = 0.16… and its gotta be 3.58 or 6.41..

odd kiln Nov 3, 2024, 4:15 PM

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[3.58, 6.41]

crisp dew Nov 3, 2024, 4:16 PM

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(3.58, 6.41) would be the domain for x < 0

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above 0 and you get two equations, x < 3.58, x > 6.41

crisp dew Nov 3, 2024, 4:17 PM

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crisp dew above 0 and you get two equations, x < 3.58, x > 6.41

i believe this is the one you’re looking for

crisp dew Nov 3, 2024, 4:17 PM

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crisp dew that = 0.16… and its gotta be 3.58 or 6.41..

5 +- root(2) from my guess

odd kiln Nov 3, 2024, 4:18 PM

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both endpoints are invalid, i think it needs at least 5 deciaml places

crisp dew Nov 3, 2024, 4:18 PM

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crisp dew

here ya go

odd kiln Nov 3, 2024, 4:19 PM

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crisp dew Nov 3, 2024, 4:19 PM

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try []?

odd kiln Nov 3, 2024, 4:19 PM

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nope

crisp dew Nov 3, 2024, 4:20 PM

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might be a rounding error one sec

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yeah i’ve no idea

odd kiln Nov 3, 2024, 4:22 PM

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that's fine. I'll ask him on Tuesday and see

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I'll reopen this channel to tell you if you are wondering

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.close

hollow crescentBOT Nov 3, 2024, 4:23 PM

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Solved

Post marked as solved by @odd kiln.

Use .unsolved if this was a mistake.

#Finding Domain of a Inverse Function Problem