#Limits (The limit is shown below)
15 messages · Page 1 of 1 (latest)
I have to solve this in two different ways, one with limit rules and special limits and the other way is by definition of the deritative but I have literally no clue
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Limits (The limit is shown below)
This is the correct one mb
,, \lim_{h \to 0} \frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h} = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h} =: f'(x)
bacc (unhelpful)
If you wanna solve this try to bring the fractions together
okay imma try that!
any tips for the other way?
btw wouldnt it be -f(h)?
oh no mb
ye i am stuck i cant
,, \lim_{h \to 0} \frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h} = \lim_{h \to 0} \frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h} = \lim_{h \to 0} \frac{\frac{-2hx - h^2}{x^2(x+h)^2}}{h} = \lim_{h \to 0} \frac{-2hx - h^2}{hx^2(x+h)^2}
Now factor an h out