Arbitrary question | Mathematics | Page 1

lost vigilBOT Sep 30, 2024, 5:53 AM

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regal tendon Sep 30, 2024, 6:09 AM

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yeah there's equal chance of each permutation of all 6 cards

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so 44 has 3×2×12 / 720 chance

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oh wait

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replacement

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that's ~~almost~~ easier?

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44 is 9 outcomes

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9 / 36

empty agate Sep 30, 2024, 6:27 AM

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regal tendon so 44 has 3×2×12 / 720 chance

if possible could you expand on how you got this? I am a bit slow, sorry

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ignoring the replacement

regal tendon Sep 30, 2024, 6:28 AM

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3×2 ways to draw two different fours, then you have 4225 left in the deck

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24/2 ways to shuffle 4225

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oh

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yeah that's wrong, the 2s are different, so it's 24 ways

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3×2×24 ways to have a deck where there are 2 fours in front

empty agate Sep 30, 2024, 6:30 AM

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would it be permutations? I am not sure sorry

regal tendon Sep 30, 2024, 6:30 AM

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yes

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720 is 6!

empty agate Sep 30, 2024, 6:30 AM

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I remember that is when order matters, for 22 and 44 would that be the case?

regal tendon Sep 30, 2024, 6:30 AM

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yes

empty agate Sep 30, 2024, 6:31 AM

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ah no wonder, tysm\

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ever since dropping maths extension I have becomes icnredibly terrible at combinatorics

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xd

#Arbitrary question