I'm trying to perform (\frac{2x^{3}-3x^{2}-8x-3}{2x+1}) to factor the numerator, and the complete table of Synthetic Division I end up with is:
[\begin{array}{c|rrrr}
-\frac{1}{2} & 2 & -3 & -8 & -3 \
& & -1 & 2 & 3 \
\hline
& 2 & -4 & -6 & 0
\end{array}]
But strangely, the answer (2x^{3}-3x^{2}-8x-3=(2x+1)\left(2x^{2}-4x-6\right)) appears to be wrong; the true answer is (2x^{3}-3x^{2}-8x-3=(2x+1)\left(x^{2}-2x-3\right))... Why?