.

[potent shell]

what have you tried?

[ruby swallow]

nothing, I don't know how to solve it, I can't find any formula to do it, I haven't found anything on the same thing for 3 hours

[potent shell]

it helps if you carefully de-log the lhs one by one

[ruby swallow]

I looked for videos but I can't find anything

[ruby swallow]

I still don't understand

[potent shell]

$\ln x= 0$, therefore $x =...?$

[potent shell]

are you actively trying to think?

like come on

[ruby swallow]

yeah, its too late 11:00, i'm sleepy

but i'm trying

[potent shell]

answer this first

do you know what base is ln?

[ruby swallow]

is it 0?

[potent shell]

[thin yarrow]

log_base(base^exponent) = exponent
base^ log_base(x) = x

remember natural log is log_e (meaning ln x = log_e x)
so for the 1st part ln(x) = 0:

[blissful shard]

the base of ln is e

[thin yarrow]

==> e^ln x = e^0
x = 1

[blissful shard]

Yeps

[thin yarrow]

continue to do this and get rid of all the logs then solve