double check

[sage field]

No. Why did you you conclude they were false

[old jasper]

oh shoot

nvm

so i know part ii is false because the average rate of change is 4.2

not 3.2

and part i

its mostly true bnecause derivative at t=1 is greater than the average rate of the changfe

but

there could be some cases where its right

and for part iii

i know the limit definition is right but there could be a small problem where it isnt considered true

i dont know

I thought it was trick question

but i guess i was wrong

can you help me out please

[sage field]

Can you show calculation?

[sage field]

Yup

[sage field]

Wdym by this

[sage field]

Also wdym by "there could be a small problem where it isnt considered true"

[sage field]

It is unlikely you will get trick questions on an assignment like this. They are trying to help you learn not trick you

[old jasper]

so the average rate of change is calculated by p(1)-p(0)/1-0

and i found that p(1) = 8 and p(0) =4

so the average rate of change is 9-4/1 which = 4

and not 3.2

[sage field]

Howd u get this

[old jasper]

i got p p(1) and p(0) by plugging t =1

and t =0

[sage field]

I see where u may be getting confused

[old jasper]

is that wrong?

[sage field]

That is the number 4.2 not 4 times 2

4.2 = 22/5

[old jasper]

oohhh okay

the function thats given is p(t) = 4.2^t

as in 4.2

not 4x2^t

[sage field]

Yeah

[old jasper]

makes sense

okay

okay so if its not h

at first i thought it was h

but thats wrong

is it C

?

[sage field]

Yes

[old jasper]

perfect makes sense