#double integral in polar coord

50 messages · Page 1 of 1 (latest)

twilit berry
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why he get the boundries of teta as 0 to pi

wispy gateBOT
dense prawn
twilit berry
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i just understand the question actually, its bcz asked above xy plane

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but thank you for the helping

modest oak
twilit berry
dense prawn
twilit berry
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question in the photo that i sent here

dense prawn
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I replied lol

twilit berry
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yea i saw it

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but its not the answer

dense prawn
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if you say so

twilit berry
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when i read the question again i got the point

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the boundries are x^2 + y ^2 =2x and above xy-plane

dense prawn
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play with this

twilit berry
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what

dense prawn
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You will see that the circle did one rotation within (0,pi)

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that is because as I said cosine reaches radii between -2 and 2 within 0 to pi

twilit berry
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i already drew the graph

dense prawn
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it's more about understanding why 0 to pi is sufficient here

twilit berry
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i thought same thing for first

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but if you check the photo again the teta limits are 0 and pi

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that's the above xy plane

pastel pondBOT
dense prawn
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So essentially

twilit berry
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i know

pastel pondBOT
twilit berry
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i asked also chatgpt and i dunno how trustable is ir but its agree with me

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lol

dense prawn
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also i don't what you are saying

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i try to understand

twilit berry
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lemme to draw what im saying

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brb

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btw r is 2cos(teta)

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@dense prawn

dense prawn
pastel pondBOT
dense prawn
twilit berry
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for first i didn't get it bcz he scaled the whole of in this circle

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but as i read the question again i got the problem

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so everything is ok now, thx for your helping

dense prawn
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😂

twilit berry
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¯_(ツ)_/¯