#I really need help with this
107 messages · Page 1 of 1 (latest)
Not sure where to start at all…
Use similar rules as to how you would solve a normal equation
Isolate x and all
But if you multiply or divided by a negative number flip the arrow
That's basically it for linear inequalities
im still confused on how to though
at least try moving numbers around and see what happens
umm
so..
ig ill group these like terms together?
(9x+5x) and (5-7)?
like this?
is this right?
5x-7<5+9x
-5-7<9x-5x
Yes
So -5-7?
Wait why do we keep the greater/less than sign in the equation?
Ohh ok
-12 and uh
Oh
So x>?
Wait explain this
Lol
Nah like
Why is it
4x>-12 when..
OHHH
Nvm nvm I’m dumb haha
I was gonna ask why is it 4x is greater than -12 when 12 is clearly bigger but I forgot abt the negative sign so it means that it’s smaller haha
My brain almost lost it
Sorry
I*
Alright then x>?
No if 4x is greater than - 12
Isn’t x at default 1?
What x is greater than
-12*
Yea
X> 0?
Nah divide by 4 cuh 😭
4x>-12
x>-3
Divide both sides by 4
Do you have physical math classes
Or are yall doing online learning
Yes…but then again math isn’t my strong suit
Physical
I forgot everything up from 9-12th grade
Kinda ish…
But not entirely
Idek tbh wht I remember lol
Too much info to take in
Alright then with x>-3 you can graph the solution set
Ohh okay
Umm there must be another way to do it or something
Cuz strangely that answer isn’t working
Maybe uhh
Can I see how you entered it in
Oh they said to use interval notation
They don't teach us interval notation here but uh that's
(-3,inf) I think
K..I’ll try that
Oof
Yayy! It worked:)
Thank god😭🙏
It works!
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