#Curve sketching
46 messages · Page 1 of 1 (latest)
What have you tried?
Tried with long division, but it starts getting complicated
bacc
We can approximate this limit using reasoning
I wanna ask that how you come up with this?
If g(x) is a skewed asymptote of f(x) then the limit should be 1 for large x as they get very very very close to each other
Yes
bacc
You can see here what the dominant term will be for large x
[ \frac{a^2}{\frac{ab}{2}} = 1 ]
bacc
And you solve for one variable, another stays free
You can test it with desmos
@distant orchid
Sorry I am still confused
Explain
This
Yea I did a typo it's supposed to be a^2
bacc
How did you get these values?
Can you show your work?
I divided (ax-3)^2 by a^2 - bx, and it matches the first term of the quotient is-ax/b, which matches the y=mx+c format
Then is it a=4 b=8?
Can you explain why a=4 & b=8?
I got that by accident, see the part b)? I integrate it back to match the denominator, haha!
But I want to know what is the original method, maybe next time they don’t provide any hints
Sorry for your confusion.
You should get a = 4 with polynomial division
I just did polynomial division and used b = 2a
I got a = 4 or a = -4, so just a = 4 because a > 0
Since you already tried it, I assumed you did a minor mistake somewhere along the lines
So by that I can show you the solution
and compare it to mine
but you were right a = 4 and b = 8, smart of you to look at b)