#Curve sketching

46 messages · Page 1 of 1 (latest)

distant orchid
karmic sinewBOT
upbeat snow
distant orchid
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Tried with long division, but it starts getting complicated

hollow kiteBOT
upbeat snow
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We can approximate this limit using reasoning

distant orchid
upbeat snow
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If g(x) is a skewed asymptote of f(x) then the limit should be 1 for large x as they get very very very close to each other

distant orchid
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Yes

hollow kiteBOT
upbeat snow
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You can see here what the dominant term will be for large x

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[ \frac{a^2}{\frac{ab}{2}} = 1 ]

hollow kiteBOT
upbeat snow
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And you solve for one variable, another stays free

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You can test it with desmos

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@distant orchid

distant orchid
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Sorry I am still confused

upbeat snow
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Explain

distant orchid
upbeat snow
hollow kiteBOT
distant orchid
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Oh yes I got it

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Is it a=1 b=2?

upbeat snow
distant orchid
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Long division

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Whatt

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@upbeat snow

upbeat snow
distant orchid
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I divided (ax-3)^2 by a^2 - bx, and it matches the first term of the quotient is-ax/b, which matches the y=mx+c format

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Then is it a=4 b=8?

upbeat snow
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that seems more like it

distant orchid
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Can you explain why a=4 & b=8?

upbeat snow
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???

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I should explain your solution?

distant orchid
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I got that by accident, see the part b)? I integrate it back to match the denominator, haha!

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But I want to know what is the original method, maybe next time they don’t provide any hints

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Sorry for your confusion.

upbeat snow
upbeat snow
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I got a = 4 or a = -4, so just a = 4 because a > 0

upbeat snow
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So by that I can show you the solution

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and compare it to mine

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but you were right a = 4 and b = 8, smart of you to look at b)