#Similar triangle problem
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let AC = k , by sim triangles 2k = k + 10, k = 10
AC = 10
pythagaros theorem : AD^2 + DE^ = AE^
since AE = AC + CE = 10+10 = 20
DE given is 8
AD^2 = 400-64 = 336
AD = sqrt(336)
x = 336
I can’t believe that’s the answer
is it correct?
I initially got that answer but I thought it was too big to be it
well sqrt(336) is approximately 18 so it seems reasonable