#Question on Permutation involving probability
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Can you make it a little clearer
What to make clear
ok
is it fine now
Your answers are good
ik but why are you not supposed to arrange the biased dice as well
why you split it
whats the logic behind this
I know, you consider the order of the coins.
yeah
Every coin is the same, and the order in this case does not need to be considered
You flip four coins at the same time
whats with the 3c1 in ur answer
calc for X=1
no
in situation B,
biased coin is tail.
we choose one fair coin to head and other 2 fair coins to tail
in situation A,
biased coid heads. and 3 fair coins tail
oh ok
P(A) +P( B) = P(x=1)
we don't need to choose which one is biased. we just consider that the biased coin heads or tails.
It only has these two cases
we always use the method of P(A) + P(B)
x=1 x=2 x=3
if you really need to consider the order.
I think x=0 should be 3/20 rather than 3/80.
You arrange the others and consider the Biased die as separate. But I dont get why it must be considered separate
but since it is 3/80. I think the question ignores the order.
its T subscipt nb***\
if there is no infomation of x=0 and x=4.
I think it is reasonable to consider the order, after all, the question is not clear, for example, four coins can be of different denominations
Penny Nickel Dime Quarter
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But isn't that overthinking things? In short, it is good to be able to justify, the process of thinking is important to get the numbers right.
You right my flaw is that I can be too perfectionist overthinking and shi
like to understand why things work the way it does
Thanks for the method you gave
More thinking is good, and more talking will make you better. The next time you have a similar problem, you won't have to struggle, because you already know both cases.
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Bet. Have a great day bro

.solved